algebra precalculus - Solve the equation $x^4-2x^3-21x^2+22x+40=0$ whose roots are in A.P. - Mathematics Stack Exchange
Par un écrivain mystérieux
Last updated 12 mai 2024
Solve the equation $x^4-2x^3-21x^2+22x+40=0$ whose roots are in A.P. (arithmetic progression).
I don't understand this solution.
Why are the terms of AP considered as mentioned in the question and
Precalculus, 2nd Edition
Discovering Advanced Algebra Solutions Manual, PDF, Exponentiation
RD Sharma Class 12 Solutions Updated for 2023-24 Chapter 18 Maxima and Minima
Solve the equations:x^{4} - 2x^{3} - 21x^{2} + 22x + 40 = 0, the roots being in arithmetical progression.
32. Two roots of the equation ( x ^ { 4 } - 6 x ^ { 3 } + 18 x ^ { 2 } - 30 x + 25 = 0 ) are of the form ( alpha + i beta ) and ( beta + i alpha . ) Find all the roots of the equation.
Precalculus, 2nd Edition
What are the roots of x ⁴ + 2 x ³ - 21 x²- 22x + 40 = 0? - Quora
Precalculus Book
What are the roots of x ⁴ + 2 x ³ - 21 x²- 22x + 40 = 0? - Quora
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